Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        a body starts with an initial velocity of 10m/s and is moving along a straight line with constant acceleration.when the velocity of particle is 50m/s,the acceleration is reversed in direction.the velocity of particle when it again reaches the starting point is`
3 years ago

```							initial dsplacment,50^2 = 10^2 + 2as.............(1)After the v becomes 50,v^2 = 50^2 – 2as............(2)Solving both the eqns. we get,v = 10 m/s.Hence again he has to travel with velocity 10 m/s to reach starting point.
```
3 years ago
```							V2U22aS12aS125001002aS12400When the body is decelerated,V2U22aS22aS2025002aS22500So, the body starts moving in opposite direction from that point. After coming to the initial start point (after travelling S1+S2 distance back) let the velocity of the body is V`. Therefore,V2022aS1S2V22aS12aS2V224002500V24900V4900V70msHope this information will clear your doubts about the topic.
```
3 years ago
```							When body moves with initial velocity =10m/S and final velocity =50m/S Then, by applying v^2 - u^2 =2asWe get,                  2500-100=2as                                 1200=as......(1)When the body is returning then v=vm/SAnd u= 50m/S...... In this case acceleration as well as distance is in opposite direction therefore., they are taken as negative So v^2-u^2= 2(-a)(-s)      V^2 = 2(1200)+2500.....by(1)        V^2=4900          V= 70m/s
```
3 years ago
```							This question was raised in the Mixed-Objective type question of ETOOS. The options along with it were-(A) 70 m/s (B) 50 m/s (C) 10 m/s (D) 49 m/sMany people check option C) without considering the relationship between A) and D). So enough of talking let’s answer this questionu=10, v=50 in the first casei.e v²=u²+2asi.e 2as=2500-100=2400 ......(A)For second case,u=50, v=?v²=2500+2as=2500+2400=4900i.e v=sqrt(4900)=70m/s
```
2 years ago
```							Given:First,u=10 m/sv=50m/s  V^2 =u^2 +2as50^2=10^2+2as2as =2500-1002as =2400----1Second,u=50m/s  v^2=u^2+2as V^2=50^2+2as2as=v^2-2500----2From 1 and 2V^2-2500=2400V^2=4900V=√4900=70    V=70m/s
```
one year ago 605 Points
```							Dear student,Please find the answer to your question. u=10, v=50 in the first casei.e v²=u²+2asi.e 2as = 2500 – 100 = 2400 ......(A)For second case,u=50, v=?v²=2500+2as=2500+2400=4900i.e v=√(4900)=70m/s Thanks and regards,Kushagra
```
3 days ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Modern Physics

View all Questions »  ### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  ### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions