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        A body of mass m is released from top of a rough inclined plane, if the force of friction is f,then the body Will reach the bottom with what velocity ?
2 years ago

Piyush Kumar Behera
412 Points
							@Parul RajputSee in this type of problem se work energy principle,which states that,the total work done on the body=change in kinetic energy. In this question initial kinetic energy=0Let final kinetic energy be K,length of incline=hieght x cosec$\theta$ where $\theta$ is the angle of inclinationusing work-energy theorem, work done by gravity+work done by friction=K-0mg x hieght of the wedge – f x length of the inclined plane= Kmg x hieght of the wedge – f x hieght x cosec$\theta$=1/2mv2solve further to get the answer..Hope that helps!!!  please approve to encourage me thank you

2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions