A body of mass 2kg travels according to the law x(t)=pt+qt^2+rt^3 where p=3m/s q=4m/s^2 and r=5m/s^3.The force acting on the body at t=2s is

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Shailendra Kumar Sharma · Answer

Force acting on a body is given by F=ma or Now x=3t +4t 2 +5t 3 v= 3+8t+15t 2 a=8+30t Now a at 2 sec will be 68 so force acting on the object will be ma =136N

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A body of mass 2kg travels according to the law x(t)=pt+qt^2+rt^3 where p=3m/s q=4m/s^2 and r=5m/s^3.The force acting on the body at t=2s is

A body of mass 2kg travels according to the law x(t)=pt+qt^2+rt^3 where p=3m/s q=4m/s^2 and r=5m/s^3.The force acting on the body at t=2s is

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