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A body falling freely under gravity from a tower of height h covers a distance of 9/16h during the last second of its motion.then the height of tower is ???

harshal pawar , 7 Years ago

Grade 11

1 Answers

sonika p

Last Activity: 7 Years ago

h = 0.5* g * t^2

t = root (2h/g)

distance travelled in last second, 9/16h = 0.5g(2h/g) – 0.5g(root(2h/g) – 1)

simplifying we get, 81 h2 -368gh +64g2 = 0

h = 4.36m, 0.18m

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Modern Physics> A body falling freely under gravity from ...

A body falling freely under gravity from a tower of height h covers a distance of 9/16h during the last second of its motion.then the height of tower is ???

harshal pawar , 7 Years ago

sonika p

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