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A ball is thrownhorizontallywith a speed of 2p m/s from a talltower , thetangentialaccelerationafter2secondsis (take g=10 m/s2)

Navaneetha , 5 Years ago
Grade 11
anser 1 Answers
Vikas TU

Last Activity: 5 Years ago

Hiii 
Here uy = 0 
t = 2 second 
ay = 10 m/s^2
vy = ?
vy = uy + at
vy = 20 m/s
so magitude of tangential acceleration is vector sum of x and y component of velocity 
so, Vt = sqrt ( 400 + 400)
Vt = 20root2 
Caution : I have considered horizontal velocity as 20 m/s
 

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