Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
A ball is thrown horizontally with a speed of 2p m/s from a tall tower , the tangential acceleration after 2 seconds is (take g=10 m/s2)
Hiii Here uy = 0 t = 2 second ay = 10 m/s^2vy = ?vy = uy + atvy = 20 m/sso magitude of tangential acceleration is vector sum of x and y component of velocity so, Vt = sqrt ( 400 + 400)Vt = 20root2 Caution : I have considered horizontal velocity as 20 m/s
Find solution of question on doubt solving app Instasolv
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -