Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A ball is thrown horizontally with a speed of 2p m/s from a tall tower , the tangential acceleration after 2 seconds is (take g=10 m/s2)

A ball is thrown  horizontally  with a speed of 2p m/s from a tall  tower , the  tangential  acceleration  after  2  seconds  is (take g=10 m/s2) 

Grade:11

1 Answers

Vikas TU
14149 Points
one year ago
Hiii 
Here uy = 0 
t = 2 second 
ay = 10 m/s^2
vy = ?
vy = uy + at
vy = 20 m/s
so magitude of tangential acceleration is vector sum of x and y component of velocity 
so, Vt = sqrt ( 400 + 400)
Vt = 20root2 
Caution : I have considered horizontal velocity as 20 m/s
 

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free