Grade 11Modern Physics

A ball is thrown horizontally with a speed of 2p m/s from a tall tower , the tangential acceleration after 2 seconds is (take g=10 m/s2)

Navaneetha

6 Years agoGrade 11

1 Answer

Vikas TU

6 Years ago

Hiii

Here uy = 0

t = 2 second

ay = 10 m/s^2

vy = ?

vy = uy + at

vy = 20 m/s

so magitude of tangential acceleration is vector sum of x and y component of velocity

so, Vt = sqrt ( 400 + 400)

Vt = 20root2

Caution : I have considered horizontal velocity as 20 m/s

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A ball is thrown horizontally with a speed of 2p m/s from a tall tower , the tangential acceleration after 2 seconds is (take g=10 m/s2)

Navaneetha

1 Answer

Vikas TU

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