A 55 kg man holds a weight of 20 kg on his head .What is the work done by him against gravity if he moves a distance of 20 m on an incline of 1 in 5.Take g=10 metre per second square .

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Eshan · Answer

Alisha Talreja · Answer

Most understandable Theoritical Approach : 1 in 5 means he is moving a ratio of 1 (in height i.e. perpendicular) to a ratio of 5 (on ground i.e. base) .now it is gi8ven he is moving 20m on this incline ,therefore - distance = 1/5 x 20 = 4 m is his actual distance Now - work= force x disp force = (M+m)g = (55+20)10 = 750N WORK = 750 X 4 = 3000N ( ans )

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A 55 kg man holds a weight of 20 kg on his head .What is the work done by him against gravity if he moves a distance of 20 m on an incline of 1 in 5.Take g=10 metre per second square .

A 55 kg man holds a weight of 20 kg on his head .What is the work done by him against gravity if he moves a distance of 20 m on an incline of 1 in 5.Take g=10 metre per second square .

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A 55 kg man holds a weight of 20 kg on his head .What is the work done by him against gravity if he moves a distance of 20 m on an incline of 1 in 5.Take g=10 metre per second square .

A 55 kg man holds a weight of 20 kg on his head .What is the work done by him against gravity if he moves a distance of 20 m on an incline of 1 in 5.Take g=10 metre per second square .

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