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A. 10kW transmitter emits radio waves of 500 m wavelength .The no. of photon emitted per second by transmitter is of the order

Preeti bhoite , 6 Years ago
Grade 12
anser 1 Answers
Sanju

Last Activity: 6 Years ago

Energy emitted by the transmitter per sec,Et = 10kW
Energy of the wave, Ew = hc/λ 
where λ= 500m
Plugging the values gives Ew = 3.96 * 10-28
No of photons emitted per sec, n = Et / E= 10000 / 3.96 * 10-28 = 2.5 * 1031
 

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