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Grade 12Modern Physics

A. 10kW transmitter emits radio waves of 500 m wavelength .The no. of photon emitted per second by transmitter is of the order

Profile image of Preeti bhoite
8 Years agoGrade 12
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1 Answer

Profile image of Sanju
8 Years ago
Energy emitted by the transmitter per sec,Et = 10kW
Energy of the wave, Ew = hc/λ 
where λ= 500m
Plugging the values gives Ew = 3.96 * 10-28
No of photons emitted per sec, n = Et / Ew = 10000 / 3.96 * 10-28 = 2.5 * 1031
 

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