A. 10kW transmitter emits radio waves of 500 m wavelength .The no. of photon emitted per second by transmitter is of the order

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Sanju · Answer

Energy emitted by the transmitter per sec,E t = 10kW Energy of the wave, E w = hc/ λ where λ = 500m Plugging the values gives E w = 3.96 * 10 -28 No of photons emitted per sec, n = E t / E w = 10000 / 3.96 * 10 -28 = 2.5 * 10 31

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A. 10kW transmitter emits radio waves of 500 m wavelength .The no. of photon emitted per second by transmitter is of the order

A. 10kW transmitter emits radio waves of 500 m wavelength .The no. of photon emitted per second by transmitter is of the order

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A. 10kW transmitter emits radio waves of 500 m wavelength .The no. of photon emitted per second by transmitter is of the order

A. 10kW transmitter emits radio waves of 500 m wavelength .The no. of photon emitted per second by transmitter is of the order

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