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A 1.04 10e3 kg car accelerates uniformly from rest to 14.7 m/s in 3.82 s. a) What is the work done on the car?A 1.04 10e3 kg car accelerates uniformly from rest to 14.7 m/s in 3.82 s.a) What is the work done on the car in this time interval?Answer in Jb) What is the power delivered by the engine in this time interval?

Jitender Pal , 12 Years ago
Grade 9
anser 1 Answers
Askiitians Tutor Team

To find the work done on the car and the power delivered by the engine during its acceleration, we can break the problem down into manageable steps. Let's tackle each part systematically.

Calculating Work Done on the Car

The work done on an object can be calculated using the formula:

Work (W) = Change in Kinetic Energy (ΔKE)

The kinetic energy of an object is given by:

KE = 0.5 * m * v²

Where:

  • m is the mass of the object (in kg)
  • v is the final velocity (in m/s)

In this case, the car starts from rest, so its initial velocity (u) is 0 m/s. The final velocity (v) is 14.7 m/s, and the mass (m) of the car is 1.04 x 10³ kg.

First, we calculate the final kinetic energy:

KE_final = 0.5 * (1.04 x 10³ kg) * (14.7 m/s)²

Calculating this gives:

KE_final = 0.5 * 1040 * 216.09 = 112896.3 J

Since the initial kinetic energy (KE_initial) is 0 (the car starts from rest), the change in kinetic energy is:

ΔKE = KE_final - KE_initial = 112896.3 J - 0 = 112896.3 J

Thus, the work done on the car is:

W = 112896.3 J

Determining Power Delivered by the Engine

Power is defined as the rate at which work is done. The formula for power (P) is:

P = Work / Time

From our previous calculation, we found that the work done on the car is 112896.3 J. The time interval during which this work is done is 3.82 seconds.

Now, we can calculate the power:

P = 112896.3 J / 3.82 s

Calculating this gives:

P ≈ 29505.4 W

To convert this into kilowatts (kW), we divide by 1000:

P ≈ 29.5 kW

Summary of Results

In summary, the work done on the car during its acceleration is approximately 112896.3 J, and the power delivered by the engine during this time interval is about 29.5 kW.

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