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7 What percentage of the total hang time does a basketball player spend in the highest 25% of the jump?

Vicki Sharma , 12 Years ago
Grade 12
anser 1 Answers
Askiitians Tutor Team

To determine the percentage of total hang time that a basketball player spends in the highest 25% of their jump, we first need to understand the physics of jumping and how hang time is divided during the ascent and descent phases of the jump.

Understanding Hang Time in Basketball Jumps

When a player jumps, their motion can be divided into two main phases: the ascent (going up) and the descent (coming down). The total hang time is the sum of the time spent in both phases. Typically, the time spent ascending is equal to the time spent descending, assuming no external forces act on the player other than gravity.

Breaking Down the Jump

Let’s consider a simplified model of a jump:

  • The player jumps and reaches a peak height.
  • At the peak, the player momentarily stops before descending.
  • The time taken to reach the peak is equal to the time taken to fall back down.

For a basketball player, the highest 25% of the jump refers to the top quarter of the ascent. To visualize this, imagine the total hang time as a vertical line divided into four equal segments. The highest segment represents the peak of the jump, while the lower segments represent the ascent and descent.

Calculating the Time Spent in the Highest 25%

Since the ascent and descent times are equal, we can analyze the time spent in the highest 25% of the jump. If we denote the total hang time as T, the time spent in the ascent phase is T/2, and the time spent in the highest 25% of the jump can be calculated as follows:

  • Time to reach the peak (T/2) is divided into four segments.
  • Each segment represents 25% of the ascent time.
  • Therefore, the time spent in the highest 25% of the jump is (1/4) * (T/2) = T/8.

Finding the Percentage

Now, to find the percentage of the total hang time that this represents, we can set up the following equation:

Percentage of hang time in the highest 25% = (Time in highest 25% / Total hang time) * 100

Substituting our values:

Percentage = (T/8) / T * 100 = (1/8) * 100 = 12.5%

Final Thoughts

In summary, a basketball player spends approximately 12.5% of their total hang time in the highest 25% of their jump. This understanding not only highlights the dynamics of jumping but also emphasizes the importance of maximizing vertical leap for effective gameplay. Players can benefit from training that focuses on both the ascent and the control during the peak of their jump to enhance their performance on the court.

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