# # 7 A disk of diameter 15 cm is spinning at 3000 RPM. What is the acceleration of a point on the outside edge of the disk?

$\\\omega = 3000rpm=3000/60rad/sec \\=50*2\pi {rad \over sec}=100\pi {rad \over sec} \\=>\omega =100\pi {rad \over sec} \\a=a_c=\omega ^2*r \\=(100\pi)^2*0.15=151.98$