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Grade: 12th pass

                        

4 point masses are placed at corners of a square of side 2m as shown.find centre of mass of system w.r.t. the square.

3 years ago

Answers : (2)

Preeti Patnaik
13 Points
							Let O is the centre of the square.A,B,C,D are the corners of the square.A = 1kgB= 2kgC = 3 kgD = 4 kgA HAVE COORDINATES = (1,1)B has cordinates = (−1,1)C = (−1,−1)D = (1,−1)as we are moving in anti−clockwise directionX coordinated of the centre fo mass:Xcm = m1x1+m2x2+m3x3+m4x4m1+m2+m3+m4Xcm = 1−2−3+41+2+3+4 = 0Y coordinate of the centre of mass:Ycm = m1y1+m2y2+m3y3+m4y4m1+m2+m3+m4Ycm = 1+2−3−41+2+3+4 = −0.4cordinates of centre of mass with respect to origin = (0, −0.4)
						
2 years ago
Rexita Johnson
15 Points
							
As they have asked to find the centre of mass of the system with respect to the centre of the square, let us consider the geometrical centre of the square as the origin(0,0)
Let A=1kg ,B=2 kg, C=3 kg and D=4kg
And the coordinates of A,B,C and D be
(1,1),(1,-1),(-1,-1) and (-1,1) respectively
So Xcom = [(1*1)+(1*2)+(3*-1)+(4*-1)]÷[1+2+3+4]
Xcom = (1+2-3-4)÷ 10 = -0.4
Ycom =[(1*1)+(-1*2)+(-1*3)+(4*1)]÷[1+2+3+4]
Ycom = (1-2-3+4)÷ 10= 0
Therefore the coordinates of COM is (-0.4,0)
 
2 years ago
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