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A sample of water has a composition by volume of 50% H 2 , 45% CO and 5% CO 2 . Calculate the volume in litre at S.T.P. of water gas which on treatment with excess of stream will produce 5 litre H 2 . The equation for the reaction is: CO + H 2 O ® CO 2 + H 2 (A) 4.263 Litre (B) 5.263 Litre (C) 6.236 Litre (D) 7.263 Litre



A sample of water has a composition by volume of 50% H2, 45% CO and 5% CO2. Calculate the volume in litre at S.T.P. of water gas which on treatment with excess of stream will produce 5 litre H2. The equation for the reaction is:


 


                CO + H2O ® CO2 + H2


 


        (A)    4.263 Litre


        (B)    5.263 Litre


        (C)    6.236 Litre


        (D)    7.263 Litre


Grade:11

1 Answers

Simran Bhatia
348 Points
10 years ago

(B)

 

Sol.   Let suppose we use x-litre water gas at S.T.P.

 

        So it contain 0.5x litre H2.

 

        Now according to given equation

 

        CO + H2O           ®     CO2 + H2

 

        0.45x Excess              0.05x  0.5x

 

        0          –                  (0.05x + 0.45x)(0.5x + 0.45x)

 

        So total volume of H2 = 0.95x

 

        But according to question

 

        It is 5 litre

 

        So 0.95x = 5

 

        X = 5.263 litre

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