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A sample of water has a composition by volume of 50% H2, 45% CO and 5% CO2. Calculate the volume in litre at S.T.P. of water gas which on treatment with excess of stream will produce 5 litre H2. The equation for the reaction is:
CO + H2O ® CO2 + H2
(A) 4.263 Litre
(B) 5.263 Litre
(C) 6.236 Litre
(D) 7.263 Litre
(B)
Sol. Let suppose we use x-litre water gas at S.T.P.
So it contain 0.5x litre H2.
Now according to given equation
0.45x Excess 0.05x 0.5x
0 – (0.05x + 0.45x)(0.5x + 0.45x)
So total volume of H2 = 0.95x
But according to question
It is 5 litre
So 0.95x = 5
X = 5.263 litre
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