A sample of water has a composition by volume of 50% H₂, 45% CO and 5% CO₂. Calculate the volume in litre at S.T.P. of water gas which on treatment with excess of stream will produce 5 litre H₂. The equation for the reaction is:

CO + H₂O ® CO₂ + H₂

(A) 4.263 Litre

(B) 5.263 Litre

(C) 6.236 Litre

(D) 7.263 Litre

(B)

Sol.   Let suppose we use x-litre water gas at S.T.P.

        So it contain 0.5x litre H₂.

        Now according to given equation

        CO + H₂O           ®     CO₂ + H₂

        0.45x Excess              0.05x  0.5x

        0          –                  (0.05x + 0.45x)(0.5x + 0.45x)

        So total volume of H₂ = 0.95x

        But according to question

        It is 5 litre

        So 0.95x = 5

        X = 5.263 litre