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Number of electrons having l+ m value equal to zero in 26Fe may be
(A) 13
(B) 14
(C) 7
(D) 12
(AB)
Sol. 26Fe – 1s2, 2s2 2p6, 3s2 2p6, 3d6, 4s2
+ m = 0 P = 0, m = 0 i.e. s-subshell
= 1, m = –1 i.e. one orbital of p
= 2, m = 2 i.e. one of d-orbitals
hence there are 13 and 14 electron as in d-orbital it may be one or two electron having m = –2.
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