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Consider the ground state of Cr atom (Z = 24). The numbers of electrons with the azimuthal quantum numbers, = 1 and 2 are, respectively: (A) 16 and 5 (B) 12 and 5 (C) 16 and 4 (D) 12 and 4

6 years ago

Answers : (3)

Aditi Chauhan
askIITians Faculty
396 Points
							

(B)

 

Sol.    = 1 p and  = 2 for d.

 

        Now Cr has configuration

 

        1s2 2s2 2p6 3s2 3p6 3d5 4s1

 

        Hence there are 12, p-electrons and 5, d-electrons

 

6 years ago
Aviral singh
15 Points
							
Answer is 2(second option)because the correct electronic configuration  of Cr is:1s2 1s2, 2s2, 2 2p6 p6, 3s2, 3p6, 4s1, 3d5.
Usually we consider the electronic configuration  as: 1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 3d4.
But this is wrong because 3d4 wats to achieve half stability.So it takes 1 electron from 4s2.Now 4s2 becomes 4s1 and 3d4 becomes 3d5 and attains half stability.
Now, for l=1(azimuthal quantum number)subshell is p....
And here for subshell p, number of electrons(I.e.2p6 and 3p6)total no. Of electrons=12.
For l=2(azimuthal quantum number),subshell is d....and total number of electrons for subshell d(I.e.4d5)total no. Of electrons=5....
So the combination(12,5)....i.e.option(b) is correct.
 
 
 
Thank you🙏
 
one year ago
Kushagra Madhukar
askIITians Faculty
605 Points
							
Dear student,
Please find the solution to your problem.
 
Cr has electronic configuration
1s2 2s2 2p6 3s2 3p6 3d5 4s1
Hence there are 12, p-electrons and 5, d-electrons
 
Thanks and regards,
Kushagra
one month ago
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