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When photons of energy hv fall on an aluminium plate (of work function E0), photoelectrons of maximum kinetic energy K are ejected. If the frequency of the radiation is doubled, the maximum kinetic energy of the ejected photoelectrons will be
(a) 2K
(b) K
(c) K + hv
(d) K + E0
(c)
Applying Einstein''s formula for photoelectricity
If we use 2v frequency then let the kinetic energy becomes K''
So,
h. 2v = f + K''
2hv = hv – K + K''
K''= hv + K
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