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When photons of energy hv fall on an aluminium plate (of work function E0), photoelectrons of maximum kinetic energy K are ejected. If the frequency of the radiation is doubled, the maximum kinetic energy of the ejected photoelectrons will be

(a) 2K

(b) K

(c) K + hv

(d) K + E0

Amit Saxena , 11 Years ago
Grade upto college level
anser 1 Answers
Simran Bhatia

Last Activity: 11 Years ago

(c)

Applying Einstein''s formula for photoelectricity

        If we use 2v frequency then let the kinetic energy becomes K''

        So,

                h. 2v = f + K''

2hv = hv – K + K''

K''= hv + K

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