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When photons of energy hv fall on an aluminium plate (of work function E 0 ), photoelectrons of maximum kinetic energy K are ejected. If the frequency of the radiation is doubled, the maximum kinetic energy of the ejected photoelectrons will be (a) 2K (b) K (c) K + hv (d) K + E 0



When photons of energy hv fall on an aluminium plate (of work function E0), photoelectrons of maximum kinetic energy K are ejected. If the frequency of the radiation is doubled, the maximum kinetic energy of the ejected photoelectrons will be


        (a)    2K


        (b)    K


        (c)    K + hv


        (d)    K + E0


Grade:upto college level

1 Answers

Simran Bhatia
348 Points
9 years ago

(c)

Applying Einstein''s formula for photoelectricity

        If we use 2v frequency then let the kinetic energy becomes K''

        So,

                h. 2v = f + K''

2hv = hv – K + K''

K''= hv + K

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