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A nucleus ruptures into two nuclear parts, which have their velocity ratio equal to 2: 1. What will be the ratio of their nuclear size (nuclear radius)? (a) 2 1/3 : 1 (b) 1: 2 1/3 (c) 3 1/2 :1 (d) 1:3 1/2



A nucleus ruptures into two nuclear parts, which have their velocity ratio equal to 2: 1. What will be the ratio of their nuclear size (nuclear radius)?


        (a)    21/3: 1


        (b)    1: 21/3


        (c)    31/2:1


        (d)    1:31/2


Grade:10

2 Answers

Amit Saxena
35 Points
9 years ago

(b)

Applying law of conservation of momentum,

m1v1 = m2v2.

 

Rishi Sharma
askIITians Faculty 646 Points
2 years ago
Dear Student,
Please find below the solution to your problem.

As momentum is conserved,
As Velocity ratio = 2:1 ,
mass ratio = 1:2 [As,mv=constant]
Density is constant and hence ,
mass is proportional to Volume
r1^3 ​: r2^3 ​= 1:2
r1 ​: r2 ​= 1: 2^(1/3) ​

Thanks and Regards

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