A nucleus ruptures into two nuclear parts, which have their velocity ratio equal to 2: 1. What will be the ratio of their nuclear size (nuclear radius)?

        (a)    2^1/3: 1

        (b)    1: 2^1/3

        (c)    3^1/2:1

        (d)    1:3^1/2

Question

A nucleus ruptures into two nuclear parts, which have their velocity ratio equal to 2: 1. What will be the ratio of their nuclear size (nuclear radius)?

(a) 2^1/3: 1

(b) 1: 2^1/3

(c) 3^1/2:1

(d) 1:3^1/2

Amit Saxena · Answer

(b) Applying law of conservation of momentum, m 1 v 1 = m 2 v 2 .

Rishi Sharma · Answer

Dear Student,
Please find below the solution to your problem.

As momentum is conserved,
As Velocity ratio = 2:1 ,
mass ratio = 1:2 [As,mv=constant]
Density is constant and hence ,
mass is proportional to Volume
r1^3 : r2^3 = 1:2
r1 : r2 = 1: 2^(1/3)

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A nucleus ruptures into two nuclear parts, which have their velocity ratio equal to 2: 1. What will be the ratio of their nuclear size (nuclear radius)? (a) 2 1/3 : 1 (b) 1: 2 1/3 (c) 3 1/2 :1 (d) 1:3 1/2

A nucleus ruptures into two nuclear parts, which have their velocity ratio equal to 2: 1. What will be the ratio of their nuclear size (nuclear radius)?

        (a)    2^1/3: 1

        (b)    1: 2^1/3

        (c)    3^1/2:1

        (d)    1:3^1/2

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