A nucleus ruptures into two nuclear parts, which have their velocity ratio equal to 2: 1. What will be the ratio of their nuclear size (nuclear radius)?

(a) 2^1/3: 1

(b) 1: 2^1/3

(c) 3^1/2:1

(d) 1:3^1/2

(b)

Applying law of conservation of momentum,

m₁v₁ = m₂v₂.

 

Dear Student,
Please find below the solution to your problem.

As momentum is conserved,
As Velocity ratio = 2:1 ,
mass ratio = 1:2 [As,mv=constant]
Density is constant and hence ,
mass is proportional to Volume
r1^3 ​: r2^3 ​= 1:2
r1 ​: r2 ​= 1: 2^(1/3) ​

Thanks and Regards