When a hydrogen atom is raised from the ground state to an excited state,

(a) P.E decreases and K.E. increases

(b)P.E. increases and K.E decreases

(c) Both K.E. and P.E. decrease

(d) Absorption spectrum

Question

When a hydrogen atom is raised from the ground state to an excited state,

(a) P.E decreases and K.E. increases

(b)P.E. increases and K.E decreases

(c) Both K.E. and P.E. decrease

(d) Absorption spectrum

Hrishant Goswami · Answer

(b)

, where, r is the radius of orbit which increases as we move from ground to an excited state. Therefore, when a hydrogen atom is raised from the ground state, it increases the value of r. As a result of this, P.E. increases (decreases in negative) and K.E. decreases.

Kushagra Madhukar · Answer

Dear student, Please find the solution to your problem. PE = – KZe 2 /r KE = KZe 2 /2r in excited state, r increases. Hence, PE increases and KE decreases. Thanks and regards, Kushagra

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When a hydrogen atom is raised from the ground state to an excited state, (a) P.E decreases and K.E. increases (b)P.E. increases and K.E decreases (c) Both K.E. and P.E. decrease (d) Absorption spectrum

When a hydrogen atom is raised from the ground state to an excited state,

(a) P.E decreases and K.E. increases

(b)P.E. increases and K.E decreases

(c) Both K.E. and P.E. decrease

(d) Absorption spectrum

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When a hydrogen atom is raised from the ground state to an excited state, (a) P.E decreases and K.E. increases (b)P.E. increases and K.E decreases (c) Both K.E. and P.E. decrease (d) Absorption spectrum

When a hydrogen atom is raised from the ground state to an excited state, (a) P.E decreases and K.E. increases (b)P.E. increases and K.E decreases (c) Both K.E. and P.E. decrease (d) Absorption spectrum

2 Answers

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When a hydrogen atom is raised from the ground state to an excited state,

(a) P.E decreases and K.E. increases

(b)P.E. increases and K.E decreases

(c) Both K.E. and P.E. decrease

(d) Absorption spectrum