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When a hydrogen atom is raised from the ground state to an excited state, (a) P.E decreases and K.E. increases (b)P.E. increases and K.E decreases (c) Both K.E. and P.E. decrease (d) Absorption spectrum



When a hydrogen atom is raised from the ground state to an excited state,


(a) P.E decreases and K.E. increases


(b)P.E. increases and K.E decreases


(c)    Both K.E. and P.E. decrease


(d)    Absorption spectrum


Grade:upto college level

2 Answers

Hrishant Goswami
343 Points
7 years ago

(b)

, where, r is the radius of orbit which increases as we move from ground to an excited state. Therefore, when a hydrogen atom is raised from the ground state, it increases the value of r. As a result of this, P.E. increases (decreases in negative) and K.E. decreases.

Kushagra Madhukar
askIITians Faculty 629 Points
8 months ago
Dear student,
Please find the solution to your problem.
 
PE = –  KZe2/r
KE = KZe2/2r
in excited state, r increases.
Hence, PE increases and KE decreases.
 
Thanks and regards,
Kushagra

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