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Amit Saxena , 11 Years ago
Grade upto college level
anser 2 Answers
Hrishant Goswami

Last Activity: 11 Years ago

(b)

, where, r is the radius of orbit which increases as we move from ground to an excited state. Therefore, when a hydrogen atom is raised from the ground state, it increases the value of r. As a result of this, P.E. increases (decreases in negative) and K.E. decreases.

Kushagra Madhukar

Last Activity: 4 Years ago

Dear student,
Please find the solution to your problem.
 
PE = –  KZe2/r
KE = KZe2/2r
in excited state, r increases.
Hence, PE increases and KE decreases.
 
Thanks and regards,
Kushagra

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