The mass density of a nucleus varies with mass number A as(a) A2(b) A(c)Constant(d) 1/A

(c)

The nuclear radius r varies with mass number A according to the relation

r prop.  A^1/3 or A prop. r³

Dear Students
Please find below the solution to your problem.

Atomic mass = density*volume of atom.
So, density of nucleus is in depend of mass number
d= Mass no. / (4/3)​πr^3​
= A/(4/3)​π×[1.3×10^−13×A^(1/3)]^3​
= constant
= A^0

Thanks and Regards