Modern Physics> number-of-photons-emitted-per-second...

Normal 0false false falseEN-US X-NONE X-NONE/* Style Definitions */table.MsoNormalTable{mso-style-name:Table Normal;mso-tstyle-rowband-size:0;mso-tstyle-colband-size:0;mso-style-noshow:yes;mso-style-priority:99;mso-style-parent:;mso-padding-alt:0in 5.4pt 0in 5.4pt;mso-para-margin-top:0in;mso-para-margin-right:0in;mso-para-margin-bottom:10.0pt;mso-para-margin-left:0in;line-height:115%;mso-pagination:widow-orphan;font-size:11.0pt;font-family:Calibri,sans-serif;mso-ascii-font-family:Calibri;mso-ascii-theme-font:minor-latin;mso-hansi-font-family:Calibri;mso-hansi-theme-font:minor-latin;mso-bidi-font-family:Times New Roman;mso-bidi-theme-font:minor-bidi;}A radio transmitter operates at a frequency 880 kHz and a power of 10 kW. The number of photons emitted per second is(a) 1.72 × 1031(b) 1.327 × 1025(c) 1.327 × 1037(d) 1.327 × 1045

Hrishant Goswami , 11 Years ago

Grade 10

3 Answers

Hrishant Goswami

Last Activity: 11 Years ago

(a)

No. of photons emitted per sec,

Mubashara Khan

Last Activity: 6 Years ago

one kw is the power or energy per unit time

1000j/s is the power (given that power = 10kw then 10kw =10000j/s)

we know that

E=hf

where E= energy of a single photon

h= planck,s constant

f= frequency of the photon

now simplify equation as power = energy/sec

suppose n photons are emitted per second then we can say that

power=nhf

n=power/hf

n=10000/6.6 x 10^-34x880 x10³

n=1.72 x 10³¹

ankit singh

Last Activity: 4 Years ago

Electromagnetic Waves. A radio transmitter operates at a frequency of 880 kHz, and a power of 10 kW. Find the number of photons per second emitted. Suppose that the electric field amplitude of an electromagnetic wave is E₀ = 120 N/C and that its frequency is v = 50.0 MHz.