A particle projected from the origin (x = y = 0) moves in xy plane with a velocity v = 2i ^ + 4xj ^, where i ^ & j ^ are the unit vectors along x and y axis. The equation of the motion of the particle is– (a) y = x2 (b) y = 2x2 (c) y = x^2/2 (d) y = x^2/4
Amit Saxena , 11 Years ago
Grade upto college level
1 Answers
Simran Bhatia
Last Activity: 11 Years ago
(a)
v = 2i ^+4xj ^, v = v_x i ^+v_y j ^
vx = 2, vy = 4x
dy/dt=dy/dx=dx/dt
4x = dy/dx.2
Integrating, y = 2 x^2/2 = x2
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