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A particle projected from the origin (x = y = 0) moves in xy plane with a velocity v = 2i ^ + 4xj ^, where i ^ & j ^ are the unit vectors along x and y axis. The equation of the motion of the particle is–
(a) y = x2
(b) y = 2x2
(c) y = x^2/2
(d) y = x^2/4

Amit Saxena , 11 Years ago
Grade upto college level
anser 1 Answers
Simran Bhatia

Last Activity: 11 Years ago

(a)

    v = 2i ^+4xj ^, v = v_x i ^+v_y j ^

    vx = 2, vy = 4x

    dy/dt=dy/dx=dx/dt

    4x = dy/dx.2

    Integrating, y = 2 x^2/2 = x2

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