Modern Physics

The energy difference between the ground state and first excited state of an
electron in a one-dimensional rigid box of length 10-8 cm is

SHRAVAN

12 Years agoGrade

6 Answers

Arun Kumar

12 Years ago

Energy in one dimensional box is determined by

$E_{n}=n^2*h^2/8mL^2$

$\Delta E_{n}=(2^2-1)*h^2/8mL^2$

h is planck's constant

L is length of the box.

m is mass of electron

Arun Kumar

IIT Delhi

Askiitians Faculty

Mahesh

5 Years ago

Calculate the energy difference between ground sstate and first excited state is an electron in box length 10power minus 8cm

Abhishek

4 Years ago

En=n²h²/8mL²

En=n²×(6.63×10^-34)²/8×9.1×10^-34×(10^-8)²

En=3.75×10^-3×n² eV

For ground state (n=1), E1=3.75×10^-3 eV

For exited state (n=2), E2=0.015 eV

E2-E1= 11.25 eV

Abhishek Kumbhar

4 Years ago

The duration of a radar pulse is 10-0 sec. Calculate tpe uncertainty in it's energy

in electron volts. Given that Planck's constant h = 6.63 x 10·34 JS

Abhishek Kumbhar

4 Years ago

The duration of a radar pulse is 10-0 sec. Calculate tpe uncertainty in it's energy

in electron volts. Given that Planck's constant h = 6.63 x 10·34 JSec.

Abhishek Kumbhar

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The duration of a radar pulse is 10-0 sec. Calculate tpe uncertainty in it's energy

in electron volts. Given that Planck's constant h = 6.63 x 10·34 JSec.

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The energy difference between the ground state and first excited state of anelectron in a one-dimensional rigid box of length 10-8 cm is

SHRAVAN

6 Answers

Arun Kumar

Mahesh

Abhishek

Abhishek Kumbhar

Abhishek Kumbhar

Abhishek Kumbhar

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