# The energy difference between the ground state and first excited state of anelectron in a one-dimensional rigid box of length 10-8 cm is

Arun Kumar IIT Delhi
8 years ago
Energy in one dimensional box is determined by
$\fn_cm E_{n}=n^2*h^2/8mL^2$
$\Delta E_{n}=(2^2-1)*h^2/8mL^2$
h is planck's constant
L is length of the box.
m is mass of electron

Arun Kumar
IIT Delhi
Mahesh
15 Points
one year ago
Calculate the energy difference between ground sstate and first excited state is an electron in box length 10power minus 8cm

Abhishek
13 Points
one year ago
En=n²h²/8mL²
En=n²×(6.63×10^-34)²/8×9.1×10^-34×(10^-8)²
En=3.75×10^-3×n²   eV
For ground state (n=1), E1=3.75×10^-3  eV
For exited state (n=2), E2=0.015 eV
E2-E1= 11.25  eV
Abhishek Kumbhar
28 Points
3 months ago
The duration of a radar pulse is 10-0 sec. Calculate tpe uncertainty in it's energy
in electron volts. Given that Planck's constant h = 6.63 x 10·34 JS
Abhishek Kumbhar
28 Points
3 months ago
The duration of a radar pulse is 10-0 sec. Calculate tpe uncertainty in it's energy
in electron volts. Given that Planck's constant h = 6.63 x 10·34 JSec.
Abhishek Kumbhar
28 Points
3 months ago
The duration of a radar pulse is 10-0 sec. Calculate tpe uncertainty in it's energy
in electron volts. Given that Planck's constant h = 6.63 x 10·34 JSec.