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initial kinetic energy is 1/2*m*v^2
1/2 * 90 * 36 = 1620
final k.e. 1/2 * 90 * 144 =6480
increse = 6480 - 1620 = 4860 j
given mass=90
u=(6*5)/18m/s v=(12*5)/18m/s
chamge in ke=1/2*mass*(v*v-u*u)
=375J
Initial K.E.= 1/2 mv2 = 1/2×90×(6)2 = 1620
Final K.E.= 1/2 mv2 = 1/2×90×(12)2 = 6480
Increase in K.E.= Final K.E.- Initial K.E.= 6480-1620=4860.
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