Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
Close
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

⇐ BackProceed to Checkout ⇒
There are no items in this cart.
Continue Shopping

At what angle shuld a body be projected with a velocity 24m/s just to pass over the obstacle 14m high at a distance of 24m.

At what angle shuld a body be projected with a velocity 24m/s just to pass over the obstacle 14m high at a distance of 24m.

Grade:

2 Answers

Chetan Mandayam Nayakar
312 Points
9 years ago

14=24*tan(theta)-(g*)(242)/(2*242cos2(theta))

lokesh soni
37 Points
8 years ago

y=xtanθ-gx2sec2θ /2u2

14=24tanθ-10sec2θ*24*24/2*24*24

tanθ=3.8or 1

θ=45degree or 75degree

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Modern Physics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Register ICAT

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More