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a bar of mass M and length L is in pure translatory motion with centre of mass having velocity V.it collides and sticks to a second identical bar which is intially at rest.the angular velocity of the first bar is:
Conservation of linear momentum MV = Mv v=V/2Conservation of angular momentumMvL=2IwMvL=2ML^2w/3w=3V/4L counterclockwise
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