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The distance between the centres of carbon & oxygen atom in carbon monoxide gas molecule is 1.13angstrom. Locate the centre of mass of the molecule relative to carbon atom.
-> In the solution of ths ques...m1r1 = m2r2 is considered but hows its equal??
moment of masses about the c.m is zero, r cm = m 1 r 1 +m 2 r 2 / m 1 + m 2 .
As r cm = o , (about c.m means ,c.m is taken at origin)hence , m 1 r1 + m 2 r 2 =o
as per sign convention, m 1 r 1 = m 2 r 2
This is due to the conservation of centre of mass.
COM=m1r1+m2r2/m1+m2
The centre of mass remains at a fixed position and does not move.
hence COM=0
Hence m1r1+(-m2r2)=0
-ve sign shows that the centre of mass is opposite to one of the atom.
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