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ELCTRON WITH INITIAL K.E 100ev is accelerated through a P.D. OF 50V NOW de Brogile WAVELENTH BECOMES WHAT

ELCTRON WITH INITIAL K.E 100ev is accelerated through a P.D. OF 50V NOW de Brogile WAVELENTH BECOMES WHAT

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2 Answers

Chetan Mandayam Nayakar
312 Points
13 years ago

Dear Pushpak,

kinetic energy after acceleration=100+50=150eV, let E be energy,p be momentum,c be speed of light in vacuum and Me be rest mass of electron. E=150eV

E2= p2c2+m2c4, from this equation find p,λ=h/p

 

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CHETAN MANDAYAM NAYAKAR

Aman Bansal
592 Points
13 years ago

Dear Pushpak,

Using the above formula and using enery relation we can evaluate de broglies wavelength.

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