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1. The energy of a neutron of de-Broglie wavelength 1 Å will be - (Ans. 8.13 eV) 2. What voltage must be applied to an electron microscope to produce electrons of wavelength 1 Å - (Ans. 150 V)

1. The energy of a neutron of de-Broglie wavelength 1 Å will be - (Ans. 8.13 eV) 2. What voltage must be applied to an electron microscope to produce electrons of wavelength 1 Å - (Ans. 150 V)

Grade:12

1 Answers

Chetan Mandayam Nayakar
312 Points
10 years ago

According to relativity, E2=p2c2+m2c4 E is total "mass-energy", p is momentum, c is speed of light in vacuum and m is rest mass. de Broglie wavelength λ=h/p, h is Planck's constant

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