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A LIFT IS GOING VERTICALLY UPWARD WITH ACCELERATIO OF 2m/s2 AND VELOCITY OF LIFT IS 5m/s A STONE IS THROWN WITH A VELOCITY OF 3m/s.IN WHAT TIME IT COMS BACK TO THE PERSON ON THE LIFT?
let answer be 't', (3m/s)t-(gt2/2)=(5m/s)+((2m/s2)t2/2)
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