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THE ELECTRIC FIELD E AT A POINT ASSOCIATED WITH A LIGHT WAVE IS
E=100[SIN(3.14T INTO TEN POWER 15 )+SIN(6.28 TINTO TEN POWER 15 )]V/M .IF THIS LIGHT FALLS ON A METL OF WORK FUNCTION OF 2ev MAX. K.E. OF EMITTED ELECTRONS IS?
Hi
The electric field stores energy. The energy density of the electric field is given by
where
The total energy stored in the electric field in a given volume V is therefore
dV is the differential volume element
Energy associated with an electric field is 1/2ε0E2 . find the energy assosiated.
Then , apply the formula for photoelectric effect, i.e energy given = work fn + max K.E . Convert the respective units into ev.
Photoelectric effect
In effect quantitatively using Einstein's method, the following equivalent equations are used (valid for visible and ultraviolet radiation):
Energy of photon = Energy needed to remove an electron + Kinetic energy of the emitted electron
Algebraically:
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