THE ELECTRIC FIELD E AT A POINT ASSOCIATED WITH A LIGHT WAVE IS

E=100[SIN(3.14T INTO TEN POWER 15 )+SIN(6.28 TINTO TEN POWER 15 )]V/M .IF THIS LIGHT FALLS ON A METL OF WORK FUNCTION OF 2ev MAX. K.E. OF EMITTED ELECTRONS IS?

Question

THE ELECTRIC FIELD E AT A POINT ASSOCIATED WITH A LIGHT WAVE IS

E=100[SIN(3.14T INTO TEN POWER 15 )+SIN(6.28 TINTO TEN POWER 15 )]V/M .IF THIS LIGHT FALLS ON A METL OF WORK FUNCTION OF 2ev MAX. K.E. OF EMITTED ELECTRONS IS?

AskiitianExpert Shine · Answer

Hi

The electric field stores energy. The energy density of the electric field is given by

$u = \frac{1}{2} \varepsilon |\mathbf{E}|^2$

where

$\varepsilon$ is the permittivity of the medium in which the field exists

$\mathbf{E}$ is the electric field vector.

The total energy stored in the electric field in a given volume V is therefore

$\int_{V} \frac{1}{2} \varepsilon |\mathbf{E}|^2 \, \mathrm{d}V$

where

$d V$ is the differential volume element

Energy associated with an electric field is 1/2ε₀E² . find the energy assosiated.

Then , apply the formula for photoelectric effect, i.e energy given = work fn + max K.E . Convert the respective units into ev.

Photoelectric effect

In effect quantitatively using Einstein's method, the following equivalent equations are used (valid for visible and ultraviolet radiation):

Energy of photon = Energy needed to remove an electron + Kinetic energy of the emitted electron

Algebraically:

$hf = \phi + E_{k_\mathrm{max}}$

where

$h$ is Planck's constant,
$f$ is the frequency of the incident photon,
$φ = h f 0$ is the work function (sometimes denoted $W$ instead), the minimum energy required to remove a delocalised electron from the surface of any given metal,
$E_{k_\mathrm{max}} = \frac{1}{2} m v_m^2$ is the maximum kinetic energy of ejected electrons,
$f 0$ is the threshold frequency for the photoelectric effect to occur,
$m$ is the rest mass of the ejected electron, and
$v m$ is the speed of the ejected electron.

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THE ELECTRIC FIELD E AT A POINT ASSOCIATED WITH A LIGHT WAVE IS E=100[SIN(3.14T INTO TEN POWER 15 )+SIN(6.28 TINTO TEN POWER 15 )]V/M .IF THIS LIGHT FALLS ON A METL OF WORK FUNCTION OF 2ev MAX. K.E. OF EMITTED ELECTRONS IS?

THE ELECTRIC FIELD E AT A POINT ASSOCIATED WITH A LIGHT WAVE IS

E=100[SIN(3.14T INTO TEN POWER 15 )+SIN(6.28 TINTO TEN POWER 15 )]V/M .IF THIS LIGHT FALLS ON A METL OF WORK FUNCTION OF 2ev MAX. K.E. OF EMITTED ELECTRONS IS?

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