Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A hydrogen atom moving with a speed 'v' absorbs a photon of wavelength 127nm and stops.Then the value of 'v' is nearly........... Pls explain.......

A hydrogen atom moving with a speed 'v' absorbs a photon of wavelength 127nm and stops.Then the value of 'v' is nearly...........


 


Pls explain.......

Grade:12

2 Answers

aman gupta
27 Points
10 years ago

energy of a photon is = hc/λ

visible light lies in 390-750 nm 

maximum energy for 390 nm

h=6.626 x  10-34 

c= 3 x 108

λ=390 x 10-9

 

E=5.09 x 10-19 Joules

Geoffrey Richards
34 Points
10 years ago

The ans comes out to be v=3.1 m/s

 

Use the formula     lambda = h/mv

lambda = 127nm

h = 6.626*10-34 Js

mass (m)= 1.67*10-27 kg

 

Now evaluate do it as a practice ...

U get v =3.1 m/s

 

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free