Last Activity: 13 Years ago
energy of a photon is = hc/λ
visible light lies in 390-750 nm
maximum energy for 390 nm
h=6.626 x 10-34
c= 3 x 108
λ=390 x 10-9
E=5.09 x 10-19 Joules
The ans comes out to be v=3.1 m/s
Use the formula lambda = h/mv
lambda = 127nm
h = 6.626*10-34 Js
mass (m)= 1.67*10-27 kg
Now evaluate do it as a practice ...
U get v =3.1 m/s
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Last Activity: 2 Year ago(s)