In a photoelectric experiment, when em wave given by E=E0sinwt is incident, electron is just ejected.When E=E0sin2wt is incident Kmax=K1 and when E=E0cos6wt is incident kmax = k2. find k2/k1

E = E_osinwt

frequency(v) = w/2pi so

E = hv = h(w/2pi) = energy of light photon

for this elergy electron is just ejected so this value of Energy is workfunction metal ..

@ = workfunction = h(2pi/w)        .............1

for eq E = E_osin2wt , v = 2w/2pi = w/pi

k₁ = hv - @ = h(w/pi) - h(w/2pi) = hw/2pi       .............2

for eq E = E_osin6wt , v = 6w/2pi = 3w/pi

K₂ = hv - @ = 3wh/pi - wh/2pi = 5wpi/2          ...........3

k₂/k₁ = 5

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