Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
What is the probability that a radioactive atom having a mean life of 10 days decays during the fifth day?(Ans.....0.39)
probablity = (1-e-(lamda)t) (lamda = decay constant) mean life = 1/lamda 10 = 1/lamda lamda = 1/10 day-1 now at t = 5days probablity = (1-e-1/2) =(1- 1/e1/2)=0.39 (value of e is around 2.8)
probablity = (1-e-(lamda)t) (lamda = decay constant)
mean life = 1/lamda
10 = 1/lamda
lamda = 1/10 day-1
now at t = 5days
probablity = (1-e-1/2)
=(1- 1/e1/2)=0.39 (value of e is around 2.8)
Find solution of question on doubt solving app Instasolv
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -