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What is the probability that a radioactive atom having a mean life of 10 days decays during the fifth day?(Ans.....0.39)
probablity = (1-e-(lamda)t) (lamda = decay constant) mean life = 1/lamda 10 = 1/lamda lamda = 1/10 day-1 now at t = 5days probablity = (1-e-1/2) =(1- 1/e1/2)=0.39 (value of e is around 2.8)
probablity = (1-e-(lamda)t) (lamda = decay constant)
mean life = 1/lamda
10 = 1/lamda
lamda = 1/10 day-1
now at t = 5days
probablity = (1-e-1/2)
=(1- 1/e1/2)=0.39 (value of e is around 2.8)
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