An electron spends about 10^-8s in an excited state before it drops to a lower state by emiting a photon. How many revolution does an electron in an n=2 bohr orbit make in 1.00*10^-8s? (ans_8.23*10^6 revolution)

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vikas askiitian expert · Answer

velocity in any orbit = (2.18*10 6 )/n m/s V 2 = (2.18*10 6 )/2 m/s radius of any orbit = (52.9)*10 -12 n 2 m r 2 = (52.9*10 -12 )4 m time in which electron completes one revolution is T = 2pir 2 /V 2 T =12*10 -16 let it completes n crevolution so total time taken = n(12*10 -16 ) n(12*10 -16 ) = 10 -8 n = 8.23 * 10 6 revolutions

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An electron spends about 10^-8s in an excited state before it drops to a lower state by emiting a photon. How many revolution does an electron in an n=2 bohr orbit make in 1.0010^-8s? (ans_8.2310^6 revolution)

An electron spends about 10^-8s in an excited state before it drops to a lower state by emiting a photon. How many revolution does an electron in an n=2 bohr orbit make in 1.0010^-8s? (ans_8.2310^6 revolution)

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