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An electron spends about 10^-8s in an excited state before it drops to a lower state by emiting a photon. How many revolution does an electron in an n=2 bohr orbit make in 1.00*10^-8s? (ans_8.23*10^6 revolution)
velocity in any orbit = (2.18*106)/n m/s V2 = (2.18*106)/2 m/s radius of any orbit = (52.9)*10-12n2 m r2 = (52.9*10-12)4 m time in which electron completes one revolution is T = 2pir2/V2 T =12*10-16 let it completes n crevolution so total time taken = n(12*10-16) n(12*10-16) = 10-8 n = 8.23 * 106 revolutions
velocity in any orbit = (2.18*106)/n m/s
V2 = (2.18*106)/2 m/s
radius of any orbit = (52.9)*10-12n2 m
r2 = (52.9*10-12)4 m
time in which electron completes one revolution is
T = 2pir2/V2
T =12*10-16
let it completes n crevolution so total time taken = n(12*10-16)
n(12*10-16) = 10-8
n = 8.23 * 106 revolutions
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