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1.5mW of 400nm light is directed at a photoelectric cell. If 0.1% of the incident photon produce photoelectrons,find the current in the cell? (Answer is 0.48microA)....PLS answer fast ........
for wavelength 400 nm , energy of each photon be E=hc/lamda
n number of photons will have total energy n(E) ...
power of photon beam is given so
n(E) = 1.5mW .....
n = 1.5/E (number of photons striking per second)
0.1% photons extract electrons so
ne(number of ejected electrons) = 0.1% of n
now photo current = nq=ne (e is electronic charge)
put all the values & u will get ans 0.48microA current
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