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A sample of monoatomic hydrogen gas contains n atoms all in 3rd exited state.Find the minimum value of n so that on subsequent de-exitation all possible different energy photons are emitted?

Ans:4

M.vs vivek vardhan , 15 Years ago
Grade 12
anser 1 Answers
SAGAR SINGH - IIT DELHI

Dear student,

Use the energy equation

E = -{k_e e^2 \over 2r_n } = - { (k_e e^2)^2 m_e \over 2\hbar^2 n^2} = {-13.6 \mathrm{eV} \over n^2}
 we will get n=4(min)

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