Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
An electron, an alpha particle, and a proton have the same kinetic energy.Which of these particles has the shortest, de-Broglie wavelength?
kinetic energy is given by E= (1/2)mv^2.Same kinetic energy means electron has highest vellocity( to make for its small mass)Assume mass of electron as 1 unit.mass of proton aprrox 1836 and mass of alpha particle is 4 times ie is 7344.now calculate velocity in each caseFor electron v= squareroot(2E)F0r proton v = squareroot(2E/1836)for alpha particle v=squareroot(2E/7344)Also de-Broglie wavelength is given by Lambda= h/mvNow calculate momentum in easch caseFor electron mv= squareroot(2E)*1For proton v = squareroot(2E/1836)*1836For alpha particle v=squareroot(2E/7344)*7344Clearly electron has least momentum. Hnece it has largest de-Broglie wavelength. And Alpha particle has least wavelength.
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !