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You throw a ball with a speed of 25.3 m/s at an angle of 42.0° above the horizontal directly toward a wall as shown in Fig. The wall is 21.8 m from the release point of the ball. (a) How long is the ball in the air before it hits the wall? (b) How far above the release point does the ball hit the wall? (c) What are the horizontal and vertical components of its velocity as it hits the wall? (d) Has it passed the highest point on its trajectory when it hits?

You throw a ball with a speed of 25.3 m/s at an angle of 42.0° above the horizontal directly toward a wall as shown in Fig. The wall is 21.8 m from the release point of the ball. (a) How long is the ball in the air before it hits the wall? (b) How far above the release point does the ball hit the wall? (c) What are the horizontal and vertical components of its velocity as it hits the wall? (d) Has it passed the highest point on its trajectory when it hits?

Grade:11

1 Answers

Aditi Chauhan
askIITians Faculty 396 Points
8 years ago
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Therefore, the time of flight of the ball is 1.15 s .
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Round off to two significant figures,
y = 13 m
Therefore, the vertical distance travelled by the ball in 1.15 s is 13 m .

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Therefore, the vertical component of final velocity of the ball before hitting the wall is 5.65 m.
The horizontal component of velocity remains unchanged during its flight,

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Therefore, the horizontal component of final velocity of ball, before hitting the wall is 18.8 m/s.
(d)
From part (c) it is clear that vertical component of final velocity of ball is 5.65 m/s , and is positive. Therefore the ball is yet to reach its maximum height but collided with the wall before doing the same.

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