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Grade 12th passMechanics

You have answered the question but did told about Azimuth .Question is repeating A canon fires two shells in succession with velocity 200m/s,the first at 60° and the second at 45° with horizontal, the azimuth being the same. Find the time interval between firings if the shell collide.

Profile image of Neehal Raj
9 Years agoGrade 12th pass
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1 Answer

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ApprovedApproved Tutor Answer1 Year ago

To determine the time interval between the firings of the two shells from the cannon, we first need to analyze their trajectories. Both shells are fired at different angles but with the same initial velocity. The concept of azimuth refers to the angle of the projectile's path in the horizontal plane, which remains constant in this case. Let's break down the problem step by step.

Step 1: Understanding the Trajectories

When a projectile is fired, its motion can be analyzed in two dimensions: horizontal (x-axis) and vertical (y-axis). The equations of motion for both shells can be derived from the initial velocity and the angles of projection.

Equations of Motion

The horizontal and vertical components of the initial velocity for each shell can be calculated as follows:

  • For the first shell (60°):
    • Vx1 = V * cos(60°) = 200 * 0.5 = 100 m/s
    • Vy1 = V * sin(60°) = 200 * (√3/2) ≈ 173.21 m/s
  • For the second shell (45°):
    • Vx2 = V * cos(45°) = 200 * (√2/2) ≈ 141.42 m/s
    • Vy2 = V * sin(45°) = 200 * (√2/2) ≈ 141.42 m/s

Step 2: Time of Flight

The time of flight for each shell can be calculated using the formula:

Time of flight (T) = (2 * Vy) / g, where g is the acceleration due to gravity (approximately 9.81 m/s²).

  • For the first shell:
  • T1 = (2 * 173.21) / 9.81 ≈ 35.29 seconds

  • For the second shell:
  • T2 = (2 * 141.42) / 9.81 ≈ 28.84 seconds

Step 3: Horizontal Distance

Next, we need to find the horizontal distance traveled by each shell. The horizontal distance (D) can be calculated using:

D = Vx * T.

  • For the first shell:
  • D1 = 100 * 35.29 ≈ 3529 m

  • For the second shell:
  • D2 = 141.42 * 28.84 ≈ 4071.74 m

Step 4: Collision Condition

For the shells to collide, they must travel the same horizontal distance at the same time. Let’s denote the time interval between the firings as Δt. The second shell is fired after the first, so its time of flight can be expressed as:

T2 + Δt = T1.

Step 5: Solving for the Time Interval

Substituting the values we calculated:

28.84 + Δt = 35.29.

Δt = 35.29 - 28.84 = 6.45 seconds.

Final Result

The time interval between the firings of the two shells, ensuring they collide, is approximately 6.45 seconds.

In summary, by analyzing the components of motion and applying the equations of projectile motion, we were able to determine the necessary time interval for the shells to collide. This approach illustrates the importance of breaking down complex problems into manageable parts, allowing for a clearer understanding of the underlying physics.