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Work done in increasing the size of a soap bubble from a radius of 3cm to 5cm is nearly (Surface tension of soap solution = 0.03 Nm -1 ) (a) 0.2 pmJ (b) 2pmJ (c) 0.4pmJ (d) 4pmJ

Work done in increasing the size of a soap bubble from a radius of 3cm to 5cm is nearly (Surface tension of soap solution = 0.03 Nm-1)
(a) 0.2 pmJ
(b) 2pmJ
(c) 0.4pmJ
(d) 4pmJ

Grade:11

1 Answers

Kevin Nash
askIITians Faculty 332 Points
6 years ago

(c) W = 2T?V

W = 2T4p[(52) – (3)2] * 10-4

= 2 * 0.03 * 4p [25 – 9] * 10-4 J = 0.4p * 10-3 J

0.4pmJ

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