Grade 12th passMechanics
With what velocity a body is thrown distance cover in 6th&5th second are equal
1 Answer
Soumya Ranjan Mohanty
Dear student,
The distance travelled in nth second = u+a/2 (2n-1)
for n=5, distance S5 = u - 44.1 (putting n=5 and a=-9.8)
Distance covered in the 6th second: (put n = 6, a=-9.8) S6 = u - 53.9
the body is projected upwards,so distance travelled in two different time intervals will be same when at one time it is going up and the other time it is coming down.Here, during 5th second, the object was moving up, and during 6th second, the object is coming down.
Therefore, the distance S6 will be negative.S6 = -(u - 53.9)as s5=s6
u - 44.1 = -u + 53.9
2u = 98
u=49 m/s [Ans]
Thanks,
Soumya Ranjan Mohanty.
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