With what minimum speed a particle be projected from the origin so that it is able to pass through a given point (30,40)

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Khimraj · Answer

For min velocity point (30,40) will be max height point. Then tan = 40/30 = 4/3 H = 40 = u 2 sin 2 /2g 40 = u 2 (4/5) 2 /2*10 u 2 = 800*25/16 = 1250 then u = 25 m/s Hope it clears. If you like answerthen please approve it.

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With what minimum speed a particle be projected from the origin so that it is able to pass through a given point (30,40)

With what minimum speed a particle be projected from the origin so that it is able to pass through a given point (30,40)

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With what minimum speed a particle be projected from the origin so that it is able to pass through a given point (30,40)

With what minimum speed a particle be projected from the origin so that it is able to pass through a given point (30,40)

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