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Grade: 11
        
why the path of projectile is parabola and not as like horizontal?
2 years ago

Answers : (1)

Umakant biswal
5349 Points
							
@ gopala 
suppose a projectile of mass m is projected with velocity u at an angle theta with the ground . 
the horizontal component = u cos theta ( remain constant ) 
the horizontal displacement at any time t is x = uxt = ut cos theta 
t = x/ u cos theta 
the vertical component is given by u (y ) = u sin theta 
the vertical displacement at any time t is 
Y = XTAN THETA – G X SQUARE / { 2 U SQUARE COS SQUARE THETA } 
and , this above equation is a equation of a parabola . 
so, the path of projectile is a parabola 
HOPE IT CLEARS 
ALL THE BEST ..
2 years ago
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