Grade 11Mechanics
Why is it easier to pull than to push a lawnmower explain with derivation.
Why is it easier to pull than to push a lawnmower explain with derivation.
4 Answers
Mrigank
Approved Tutor Answer8 Years agoWhen you are pulling out pushing any object on any frictional surface, the force is always at some angle with the horizontal, except when you push or pull exactly parallel to the ground. What you need to do is just to divide the force in its components and rule the question.Let us break the problem in two cases. Let us suppose you are pulling the object at an angle theta with horizontal. Now divide the force into its components. The perpendicular component will be in upwards direction which will decrease the normal force as a result of which frictional force will decrease. If you are pushing the object, the perpendicular component will be towards the ground increasing the normal which will increase friction. Therefore pulling is easier than pushing.
Vaibhav yadav
at pulling time frictional force fs = coefficient of friction × R (normal force ) is less than pushing time because vertical component is added in lawnmower weight at the pushing which increase normal force and hence frictional force is increased
Nikita arora
The force applied to move a body depends on effective force applied on it including its weight . As effective weight in case of pulling is less than in the pushing ,less force is required in the pulling .Hence it is easier to pull than to push . In case of pulling ,effective weight of lawn mower = mg -fsinangle In case of pushing ,effective weight of lawn mower =mg +fsinangle
Rishi Sharma
Dear Student,
Please find below the solution to your problem.
When you are pulling out pushing any object on any frictional surface, the force is always at some angle with the horizontal, except when you push or pull exactly parallel to the ground. What you need to do is just to divide the force in its components and rule the question.Let us break the problem in two cases. Let us suppose you are pulling the object at an angle theta with horizontal. Now divide the force into its components. The perpendicular component will be in upwards direction which will decrease the normal force as a result of which frictional force will decrease. If you are pushing the object, the perpendicular component will be towards the ground increasing the normal which will increase friction. Therefore pulling is easier than pushing.
Thanks and Regards
Please find below the solution to your problem.
When you are pulling out pushing any object on any frictional surface, the force is always at some angle with the horizontal, except when you push or pull exactly parallel to the ground. What you need to do is just to divide the force in its components and rule the question.Let us break the problem in two cases. Let us suppose you are pulling the object at an angle theta with horizontal. Now divide the force into its components. The perpendicular component will be in upwards direction which will decrease the normal force as a result of which frictional force will decrease. If you are pushing the object, the perpendicular component will be towards the ground increasing the normal which will increase friction. Therefore pulling is easier than pushing.
Thanks and Regards
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