Flag Mechanics> While a 1700-kg automobile is moving at a...
question mark

While a 1700-kg automobile is moving at a constant speed of 15 m/s, the motor supplies 16 kW of power to overcome friction, wind resistance, and so on. {a) What is the effective retarding force associated with all the frictional forces combined? (b) What power must the motor supply if the car is to move up an 8 .0 % grade (8 .0 m vertically for each 10 0 m horizontally) at 15 m/s? (c) At what downgrade, expressed in percentage terms, would the car coast at 15 m/s?

Ashhfaq , 5 Years ago
Grade 12th pass
anser 1 Answers
Harsh

Last Activity: 5 Years ago

We know that power is equal to force*velocity
Hence,
16000=f*15
F=16000/15
=1066.6  N
For vertical grade.
V²=2as
225=2a*10
a=2.25/2
a=1.125 m/s²
In moving vertically upwards it there will be weight
force acting downwards and the vehicle will try moving upwards
Balancing the forces
mg+ma=Fnet
m(g)+a =Fnet
Fnet=18912 N
Power=f*v
Power=18912*15
Power =283.68 KW
Now for downgrade follow the same step in reverse order to find new displacement

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...