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Grade: 12th pass
        
Where is the center of mass of the three particles shown in Fig. 7-26?
 
one year ago

Answers : (2)

Khimraj
3008 Points
							
Xcm = (3*0 +8*1 + 4*2)/(3+8+4) = 16/15
Ycm = (3*0 +8*2 + 4*1)/(3+8+4) = 20/15
so CM = (16/15, 20/15)
Hope it clears............................................
one year ago
k sibin
37 Points
							
Xcm=m1x1+m2x2+m3x3\m1+m2+m3
Ycm=m1y1+m2y2+m3y3/m1+m2+m3
Xcm=0+8+8/15
Ycm=0+4+16/15
Xcm=16/15
Ycm=20/15=4/3
cm=(16/15,4/3)
one year ago
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