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`        Where is the center of mass of the three particles shown in Fig. 7-26? `
one year ago

## Answers : (2)

Khimraj
3008 Points
```							Xcm = (3*0 +8*1 + 4*2)/(3+8+4) = 16/15Ycm = (3*0 +8*2 + 4*1)/(3+8+4) = 20/15so CM = (16/15, 20/15)Hope it clears............................................
```
one year ago
k sibin
37 Points
```							Xcm=m1x1+m2x2+m3x3\m1+m2+m3Ycm=m1y1+m2y2+m3y3/m1+m2+m3Xcm=0+8+8/15Ycm=0+4+16/15Xcm=16/15Ycm=20/15=4/3cm=(16/15,4/3)
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions