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`        When a mass 8kg is just released,its kinetic energy when it touches the ground is(pulley is weightless and frictionless)`
2 years ago

downey zer
73 Points
```							when 8 kg will move down by 7m ,4kg has to go up by 7m total work done on system by gravity = 8g*7-4g*7=28gthis is equal to the total change in kE of the system let the velocity of 8kg be v since 4kg is connected to 8kg by string therefore 4kg must also have velocity vtotal kE = 1/2(4+8)v2KE of 8kg= 1/2(8)v2 KE of 8kg/ Total KE=2/3But total kE = 28gtherefore KE of 8kg=2/3*28g=56/3ghope that helps. please approve the answer if it did
```
2 years ago
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