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```
When a block of mass 0.5 kg is suspended from the end of a spring, it stretches by 0.02 m. (a) Find the force constant if the spring. (b) The block is given by a sharp impulse, so that it moves upwards with a velocity of ✓20 ms-1. How high will it rise?

```
3 years ago

Spartan 007
20 Points
```							A-)  F=-kx       mg=-k(0.02)        -k=0.5*10/0.02         k=-250N/m. 77777777777777777777777777777777777777777777777777777777777777777777
```
3 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions