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`        What will be the height above surface of the earth where the value of gravitational acceleration is one forth of that at surface ?`
one year ago

Vikas TU
9766 Points
```							Gravity acceleration above the earth is given by the formulae: => geff. = GM/(h + R)^2where h is the distance from the earth’s surface.g at surface => GM/R^2Now when it is 1/4th of when it is at surface that is geff. = g/4Putting both the values we get,GM/4R^2 = GM/(h + R)^2(h + R)^2 = 4R^2h + R = 2Rh = RHence at R distance it will be 1-fourth to the value at surface.
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions