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What should be the minimum angular speed of the earth be as that object world fly of it surface Take g=10mn and Rg=6400km

Gaurav , 7 Years ago
Grade 12th pass
anser 1 Answers
Aslan

Last Activity: 7 Years ago

The variation of acceleration due to gravitation due to rotation of earth is obtained by the relation,
g’ = g – Rω2cos2λ where λ is latitude
At equator, ge = g – Rω2
When g = Rω2, ge = 0
Thus, ω = root(g/R)
= root(10/6400)
= 0.0395 revolutions per second (or 17 times the present value).
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