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What's wrong with my approach?
If the surface is smooth then work done should be equal to kinetic energy and so the soln.

apoorv mishra , 4 Years ago
Grade 11
anser 2 Answers
abhay gupta
Dear student,
Here’s your solution

you can’t use workdone = f*d here because you’re already equated work done = gain in kinetic energy
both are similar, if you proceed your calculation in gain in kinetic energy then you’ll have the formula f*d
628-2354_Screenshot 2021-03-13 135427.png
so you can’t use the resultant formula as here’s initial velocity is 0

go step by step
i.e. W = ½ m(v2– u2) = ½ mv2
then differentiate it.

Askiitians expert
Ankit
Last Activity: 4 Years ago
Vibekjyoti Sahoo
you can’t use workdone = f*d here because you’re already equated work done = gain in kinetic energy
both are similar, if you proceed your calculation in gain in kinetic energy then you’ll have the formula f*d
628-2354_Screenshot 2021-03-13 135427.png
so you can’t use the resultant formula as here’s initial velocity is 0

go step by step
i.e. W = ½ m(v2– u2) = ½ mv2
then differentiate it.
Last Activity: 4 Years ago
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