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Grade 11Mechanics

What's wrong with my approach?
If the surface is smooth then work done should be equal to kinetic energy and so the soln.

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Profile image of apoorv mishra
5 Years agoGrade 11
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2 Answers

Profile image of abhay gupta
5 Years ago
Dear student,
Here’s your solution

you can’t use workdone = f*d here because you’re already equated work done = gain in kinetic energy
both are similar, if you proceed your calculation in gain in kinetic energy then you’ll have the formula f*d
628-2354_Screenshot 2021-03-13 135427.png
so you can’t use the resultant formula as here’s initial velocity is 0

go step by step
i.e. W = ½ m(v2– u2) = ½ mv2
then differentiate it.

Askiitians expert
Ankit
Profile image of Vibekjyoti Sahoo
4 Years ago
you can’t use workdone = f*d here because you’re already equated work done = gain in kinetic energy
both are similar, if you proceed your calculation in gain in kinetic energy then you’ll have the formula f*d
628-2354_Screenshot 2021-03-13 135427.png
so you can’t use the resultant formula as here’s initial velocity is 0

go step by step
i.e. W = ½ m(v2– u2) = ½ mv2
then differentiate it.